Professor Wood has given us a simple physics lesson explaining why the "official" collapse theory (to the extent that there even is one) cannot possibly be true.

Conservation of Momentum:

The amount of momentum (p) that an object has depends on two physical quantities: the mass and the velocity of the moving object.

p = mv

where p is the momentum, m is the mass, and v the velocity.

If momentum is conserved it can be used to calculate unknown velocities following a collision.

(m1 * v1)i + (m2 * v2)i = (m1 * v1)f + (m2 * v2)f

where the subscript i signifies initial, before the collision, and f signifies final, after the collision.

If (m1)i = 0, and (v2)i = 0, then (v2)f must =0.
So, for conservation of momentum, there cannot be pulverization.

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If we assume the second mass is initially at rest [(v2)i = 0], the equation reduces to

(m1 * v1)i = (m1 * v1)f + (m2 * v2)f

As you can see, if mass m1 = m2 and they "stick" together after impact, the equation reduces to ,

(m1 * v1)i = (2m1 * vnew)f

or vnew = (1/2) * v1

If two identical masses colliding and sticking together, they will travel at half the speed as the original single mass.

Conservation of Energy:

In elastic collisions, the sum of kinetic energy before a collision must equal the sum of kinetic energy after the collision. Conservation of kinetic energy is given by the following formula:

(1/2)(m1 * v21)i + (1/2)(m2 * v22)i = (1/2)(m1 * v21)f + (1/2)(m2 * v22)f + (Pulverize) + (Fail Floor Supports)

where (Pulverize) is the energy required to pulverize a floor and (Fail Floor Supports) is the energy required to fail the next floor.

If (1/2)(m1 * v21)i + (1/2)(m2 * v22)i = (Pulverize) + (Fail Floor Supports), there well be no momentum transfer.

In reality, (1/2)(m1 * v21)i + (1/2)(m2 * v22)i < (Pulverize) + (Fail Floor Supports),

So, for conservation of energy, we must assume there is some additional energy such that,

(1/2)(m1 * v21)i + (1/2)(m2 * v22)i + (Additional Energy) = (Pulverize) + (Fail Floor Supports),

where (Additional Energy) is the additional amount of energy needed to have the outcome we observed on 9/11/01.

Assuming elastic collisions:

Assume that the top floor stays intact as a solid block weight, Block-A. Start the collapse timer when the 109th floor fails. At that instant, assume floor 108 miraculously turns to dust and disappears. So, Block-A can drop at free-fall speed until it reaches the 108th floor. After Block-A travels one floor, it now has momentum. If all of the momentum is transferred from Block-A to Block-B, the next floor, Block-A will stop moving momentarily, even if there is no resistance for the next block to start moving.

(m1 * v1)i = (m2 * v2)f

If Block-A stops moving, after triggering the next sequence, the mass of Block-A will not arrive in time to transfer momentum to the next "pancaking" between Block-B and Block-C. In other words, the momentum will not be increased as the "collapse" progresses.

However, as we can observe, the building disintegrated from the top down and there was no block of material.